Tech Support > Computer Hardware > Microprocessors > How many resistor on CAN Bus?
How many resistor on CAN Bus?
Posted by ciani.giulia@gmail.com on August 22nd, 2007


Hi,

I'm working with a CAN bus based on CANOPEN protocol. My bus lenght
is about 200m and the speed is 250Kb/s. I have 10 nodes on this bus,
the master is at one end of the bus, on the other end I've got the
resistance of 120 Ohm. The system works in a curious mode. Sometimes
the master receives messages with RTR bit at 1, when it should be 0,
for example in SDO messages, and sometimes not. Even if I reduce the
speed at 125, the same thing happens! So, I don't think is a speed
problem. I made a test, and it works: if I put a resistance also on
the second last node, I do not receive unexpected RTR bit at 1, and
the bus works correctly from the first to the last node.
Can somebody explain this to me?

Giulia

Posted by James Beck on August 22nd, 2007


In article <1187797827.661554.301610@i13g2000prf.googlegroups .com>,
ciani.giulia@gmail.com says...
resistors at each end of the line???


Posted by CBFalconer on August 22nd, 2007


ciani.giulia@gmail.com wrote:
I know nothing about the CAN bus, but 120 ohms seems a highly
peculiar line termination value. 70, or 100 ohms is more likely.
Check it. Do you have both ends of the bus terminated?

--
Chuck F (cbfalconer at maineline dot net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home.att.net>



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Posted by PeteS on August 22nd, 2007


ciani.giulia@gmail.com wrote:
There are three distinct issues.

1. CAN must be terminated at each end of the main bus.

2. There is a maximum stub length to each device.

3. The controller does not sit at the 'end' of the bus in a multidrop
system.


Violate any of the above and your CAN bus may not operate as advertised.
The max speed depends on the length of the system.


Cheers

PeteS

Posted by Robert Adsett on August 22nd, 2007


In article <46CC62AB.39F692DB@yahoo.com>, CBFalconer says...
That's the usual termination value. The original description appears to
be of a bus with only a single terminator.

It's also worth noting that there is no master on a CAN bus.

Robert

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Posted by Meindert Sprang on August 23rd, 2007


<ciani.giulia@gmail.com> wrote in message
news:1187797827.661554.301610@i13g2000prf.googlegr oups.com...
There should be a resistor at BOTH ends of the bus.

Meindert



Posted by ciani.giulia@gmail.com on August 23rd, 2007


This morning I insert a resistor at the other side of the bus, near
the master, and it works! Thank you!

Posted by Hans-Bernhard Bröker on August 23rd, 2007


ciani.giulia@gmail.com wrote:
That's nastily close to the absolute maximum of 250m at that bit rate.
It's right on the rule-of-thumb limit of 50e6 (m*bit)/s. You will have
to be quite careful about cabling, transceivers and oscillator
tolerances to make that work reliably.

There is no such thing as "the" master on a CAN bus. CAN is a
multi-master bus.

Bad. Stretching the bus length this close to the limit, you absolutely
need terminators at both ends.

Posted by Heinz-Jürgen Oertel on August 25th, 2007


Robert Adsett wrote:


In the original post Giulia mentioned that she is using CANopen on top of
CAN, CANopen has an master. It is called Network Management (NMT) master.
It's only a a logical behavior, of course no influence of the physical and
Data Link Layer protocol as such.

Heinz


Posted by Robert Adsett on August 26th, 2007


In article <faplmf$127$02$1@news.t-online.com>, Heinz-Jürgen Oertel
says...
Ah, Missed that.

Robert

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