Hi all,

I am working on Unix (Solaris). I want to create a list file from the
files in my directory.

Say my directory /home/sri contains the folloiwng files & folders:
sria --> Folder
srib --> Folder
sri_f1.dat --> File
sri_f2.dat --> File
sriv3.dat --> File
am.dat --> File
blah.dat --> File

Now I want to create a new file which contains the file (not
direcotry) names starting from sri. That is, I want a list file called
sri.lst which contains below data:

sri.lst
========
sri_f1.dat
sri_f2.dat
sriv3.dat


I tried with the following command (ls -one) but this was not useful
since it also lists the directories starting from sri

ls -1 sri*


Now how can i specify Unix to consider only files and not
directories/files in subdirectories?

Any help much appriciated.

Thanks and Regards,
Srinath M. K

"Srinath M.K" wrote:
There are doubtless many ways, but the following works:

ls -p | grep -v /

--
Dr Tristram J. Scott
Energy Consultant

Srinath M.K wrote:

$ find . -type f

/Marcin

`find ./ -type f -print | tee /tmp/sri.lst`

Optionally, you can do:

`find ./ -type f -print | awk -F'/' '{print $NF}' | tee /tmp/sri.lst`

On 2004-05-14, Srinath M.K wrote:
In the specific case you describe:

ls sri*.dat

More generally (e.g., if there are files that do not end in .dat):

ls -dF sri* | grep -v '/$'

--
Chris F.A. Johnson http://cfaj.freeshell.org/shell
================================================== =================
My code (if any) in this post is copyright 2004, Chris F.A. Johnson
and may be copied under the terms of the GNU General Public License

[fu-t set]

in comp.unix.admin i read:

annoyingly most ls' don't append a space after regular files, so any file
whose name ends with a slash would be mistaken for a directory. perhaps
that's more a lesson in sensible file naming. and indeed the likelihood
of such filenames is low enough that it might even be worth ignoring.

--
a signature

mksrinath@indiatimes.com (Srinath M.K) wrote in message news:

There are many roundabout ways (no option in 'ls' will do it) to do this:

a)
/bin/ls -1dp | grep -v '/$' | grep '^sri' > /tmp/sri.list && \
mv -f /tmp/sri.list .

Note: filenames containing newlines (\n) will not handled properly.

b)
touch /tmp/sri.list && \
for _file in sri*;do
[ -f "${_file}" ] || continue
printf '%s\n' "${_file}" >> /tmp/sri.list
done
mv -f /tmp/sri.list .

Note: when a large number of files/dirs/links starting with sri are
present in your current dir., then the for loop might overflow.

c)
/bin/find . -type d ! -name . -prune -o -type f -name 'sri*' \
-print > /tmp/sri.list
mv -f /tmp/sri.list .

On 2004-05-15, rakesh sharma <sharma__r@hotmail.com> wrote:
: mksrinath@indiatimes.com (Srinath M.K) wrote in message news:
:> I am working on Unix (Solaris). I want to create a list file from the
:> files in my directory.
:>
:> Say my directory /home/sri contains the folloiwng files & folders:
:> sria --> Folder
:> srib --> Folder
:> sri_f1.dat --> File
:> sri_f2.dat --> File
:> sriv3.dat --> File
:> am.dat --> File
:> blah.dat --> File
:>
:> Now I want to create a new file which contains the file (not
:> direcotry) names starting from sri. That is, I want a list file called
:> sri.lst which contains below data:
:>
:> sri.lst
:> ========
:> sri_f1.dat
:> sri_f2.dat
:> sriv3.dat
:>
:> I tried with the following command (ls -one) but this was not useful
:> since it also lists the directories starting from sri
:>
:> ls -1 sri*
:>
:> Now how can i specify Unix to consider only files and not
:> directories/files in subdirectories?
:
: There are many roundabout ways (no option in 'ls' will do it) to do this:
:
Also a straightforward way if you have C-Kermit installed:

http://www.columbia.edu/kermit/ckermit.html

At the C-Kermit prompt, type:

directory /files /brief /output:sri.lst sri*

where:

/FILES = List only regular files
/BRIEF = List the name only
/OUTPUT:sri.lst = Put the listing in given file

You can do tons of fancy stuff with Kermit's DIRECTORY command. To give
you an idea:

C-Kermit>dir ? Enter or Return to confirm the command, or
file specification, or switch, one of the following:
/after: /dotfiles /message: /nosort /smaller-than:
/all /englishdate /nobackupfiles /not-after: /sort:
/array: /except: /nodotfiles /not-before: /summary
/ascending /files /nofollowlinks /noxfermode /type:
/backup /heading /noheading /output: /xfermode
/before: /isodate /nomessage /page /verbose
/brief /larger-than: /nopage /recursive
/directories /followlinks /norecursive /reverse
C-Kermit>

Type "help directory" at the C-Kermit> prompt for details. Prebuilt C-Kermit
binaries for Solaris can be found here:

http://www.columbia.edu/kermit/ck80binaries.html#sun

- Frank

Marcin Dobrucki <Marcin.Dobrucki@TAKETHISAWAY.nokia.com> wrote:
Add -maxdepth 1 if you want to avoid subdirectories.
--
Mark Rafn dagon@dagon.net <http://www.dagon.net/>

On 03:10 14 May 2004, Srinath M.K <mksrinath@indiatimes.com> wrote:
| I am working on Unix (Solaris). I want to create a list file from the
| files in my directory.
|
| Say my directory /home/sri contains the folloiwng files & folders:
| sria --> Folder
| srib --> Folder
| sri_f1.dat --> File
| sri_f2.dat --> File
| sriv3.dat --> File
| am.dat --> File
| blah.dat --> File
|
| Now I want to create a new file which contains the file (not
| direcotry) names starting from sri. That is, I want a list file called
| sri.lst which contains below data:
|
| sri.lst
| ========
| sri_f1.dat
| sri_f2.dat
| sriv3.dat
|
|
| I tried with the following command (ls -one) but this was not useful
| since it also lists the directories starting from sri
|
| ls -1 sri*

I'm rather fold of this:

ls -ld sri* | sed -n 's/^-.* //'

BTW, you only need -1 when you want one column sent to a terminal.
When ls is writing to a pipe or file it sends one column anyway.
(And if you think you have a counter example, make sure you haven't got an
alias getting in the way first.)

Cheers,
--
Cameron Simpson <cs@zip.com.au> DoD#743
http://www.cskk.ezoshosting.com/cs/

My initial work-around is to rebuild history.
- gary@sci34hub.sci.com (Gary Heston)

["Followup-To:" header set to comp.unix.admin.]
On 2004-05-16, Mark Rafn <dagon@dagon.net> wrote:
Except that it's a gn00 extention. Didn't OP specify `solaris'?
-prune would then be more useful, it seems.


--
j p d (at) d s b (dot) t u d e l f t (dot) n l .

mksrinath@indiatimes.com (Srinath M.K) wrote in message news:<a2fb966f.0405140210.53e28fd4@posting.google. com>...
Well, the classic form is:
ls -l | grep -v '^d'
which will return a long directory listing omitting the directories.

but you want just the file names, so you need to remove the other
columns.
ls -l | grep -v '^d' | awk '{print $9}'
will do just fine. You can redirect that into a file if required.
if you want to exclude links, just add another filter.
ls -l | grep -v '^d' | grep -v '^l' | awk '{print $9}'

The whole thing can be put in your .cshrc file as an alias:
alias lf "ls -l | grep -v '^d' | grep -v '^l' | awk '{print $9}'"

It gets a bit more difficult if you want to pass a parameter back to
the ls part of the string, such as a partially qualified file name -
but it can be done, see the man pages for your shell for details.

Bob Harvey